Will the mass and weight of an object on the earth be same as their values on Mars? The weight of a body can be measured using a spring balance and a weighing machine. Assume g = 10 m/s2 Download free printable assignments worksheets of English from CBSE NCERT KVS schools, free pdf of CBSE Class 10 English Grammar Questions chapter wise important exam questions and answers CBSE Class 10 English Grammar Questions . Answer: The weighing machine actually measures the weight of the body as the acceleration due to gravity ‘g’ is acting on the body. According to Kepler’s third law of planetary motion, the factor r3/ T2  is a constant. These important questions are provided with answers. Assume g = 10 m/s2. Gravitation | Physics | MCQ - Multiple Choice Questions | CBSE Class 9th Question 1. Use G = 6.7 × 10–11 N m2 kg–2. (b) Do the forces of friction and other contact forces arise due to gravitational attraction? F = mg Thus, because of doubling of the pull on the object due to the floor, it will become two times more difficult to pull it along the floor. Using all the given values, we have 1. Show that the time taken to go up is same as the time taken to come down. The distance between them is 3.8 × 105 km. Mass is the amount of matter contained in a body. c. The mass and weight of an object on earth are 5 kg and 49 N respectively. Explain why the value of g is zero at the centre of the earth. Chapter 15 - Improvement in Food Resources. (d) 9.8 m/s 2 Question 2. (d) 360 kg. NCERT Solutions for Class 9 Science Chapter 10 – Gravitation – Intext Questions – Page No. ⇒MB=MArB22(12rB)2=2MA TopperLearning’s Experts and Students has answered all of Gravitation of MAHARASHTRA Class 10 Physics questions in detail. S = 500 m Let the period of revolution of a planet at a distance R from a star be T. Prove that if it was at a distance of 2R from the star, its period of revolution will be 8 T. From Kepler's third law of planetary motion, we have Free Online MCQ Questions for Class 9 Science with Answers was Prepared Based on Latest Exam Pattern. This will clear students doubts about any question and improve application skills while preparing for board exams. Weight of the object on Moon, WM=16WE⇒WM=496=8.17 N  W = 50 × 10 × 10 = 5000 J. The questions involved in Balbharati Solutions are important questions At the centre of Earth, the force due to upper half of the Earth will cancel the force due to lower half. The distance between them is 3.8 × 105 km. Question from very important topics are covered by NCERT Exemplar Class 11.You also get idea about the type of questions and method to answer in your Class 11th … a. You will also love the ad-free experience on Meritnation’s Science_part_ _i_(solutions) Solutions. 3.5×1022=(6.7×10-11)(6×1024)×Ms(1.5×1011)2⇒Ms=(3.5×1022)×(1.5×1011)2(6.7×10-11)×(6×1024)=1.96×1030  kg, View NCERT Solutions for all chapters of Class 10, FREE Downloadable NCERT Solutions.Works without internet, TS Grewal Solutions for Class 12 Commerce, TS Grewal Solutions for Class 11 Commerce, Homework Questions for Class 11 Humanities, Homework Questions for Class 12 Humanities, CBSE Class 10 Board Paper Solutions for Math, CBSE Class 10 Board Paper Solutions for Science, CBSE Class 10 Board Paper Solutions for Social Science, CBSE Class 10 Board Paper Solutions for English, CBSE Class 10 Board Paper Solutions for Hindi, CBSE Class 12 Science Board Paper Solutions for Math, CBSE Class 12 Science Board Paper Solutions for Physics, CBSE Class 12 Science Board Paper Solutions for Chemistry, CBSE Class 12 Science Board Paper Solutions for Biology, CBSE Class 12 Commerce Board Paper Solutions for Economics, CBSE Class 12 Commerce Board Paper Solutions for Accountancy, CBSE Class 12 Commerce Board Paper Solutions for Business Studies, CBSE Class 12 Commerce Board Paper Solutions for Math, CBSE Class 12 Humanities Board Paper Solutions for English. Thus, from first equation of motion, we have Thus, when the period of revolution of planet at a distance R from a star is T, then from (i), we have Question 1. d. For vertical upward motion of the stone: The mass of an object is the measure of its (a) pressure. t = 5 s Questions : 1. Chapter 13 - Why do We Fall ill. Chapter 14 - Natural Resources. If the mass of A is MA, what must be the mass of B so that the value of g on B is half that of its value on A? b.The radius of planet A is half the radius of planet B. Dividing (iii) by (ii), we get Write the three laws given by Kepler. They have 15 multiple choice questions, 7 short answer questions and 4 long answer questions. Solution: The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force. After you have studied lesson, you must be looking for answers of its questions. All questions and answers from the Science_part_ _i_(solutions) Book of Class 10 Science Chapter 1 are provided here for you for free. Get the free view of chapter 1 Gravitation 10th Standard [इयत्ता १० वी] extra questions for Science and Technology Part 1 10th Standard SSC Maharashtra State Board and can use Shaalaa.com to keep it handy for your exam preparation, Chapter 2: Periodic Classification of Element, Chapter 3: Chemical reactions and equations, Science and Technology Part 1 10th Standard SSC Maharashtra State Board, CBSE Previous Year Question Paper With Solution for Class 12 Arts, CBSE Previous Year Question Paper With Solution for Class 12 Commerce, CBSE Previous Year Question Paper With Solution for Class 12 Science, CBSE Previous Year Question Paper With Solution for Class 10, Maharashtra State Board Previous Year Question Paper With Solution for Class 12 Arts, Maharashtra State Board Previous Year Question Paper With Solution for Class 12 Commerce, Maharashtra State Board Previous Year Question Paper With Solution for Class 12 Science, Maharashtra State Board Previous Year Question Paper With Solution for Class 10, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 12 Arts, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 12 Commerce, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 12 Science, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 10, SSC (English Medium) 10th Standard Board Exam Maharashtra State Board, SSC (Marathi Semi-English) 10th Standard [इयत्ता १० वी] Maharashtra State Board. This will clear students doubts about any question and improve application skills while preparing for board exams. If the value of g suddenly becomes twice its value, it will become two times more difficult to pull a heavy object along the floor. Hence the mass reading of 42 kg given by a weighing machine is same as the actual mass of the body. The weight of a body depends on the local acceleration due to gravity where it is placed. v = u + gt Hence, the value of g on the planet is 0.4 m/s2. Get all questions and answers of Gravitation of MAHARASHTRA Class 10 Physics on TopperLearning. Dec 09, 2020 - Short Long Answer Questions- Gravitation Class 9 Notes | EduRev is made by best teachers of Class 9. The distance between the earth and the sun is 1.5 × 1011 m. If the gravitational force between the two is 3.5 × 1022 N, what us the mass of the sun? u = 0 v=u+at⇒0=100-10×t1t1=10 s  f. The masses of the earth and moon are 6 × 1024 kg and 7.4 × 1022 kg, respectively. The weight of a 1 kilogram mass body on the earth will be (a) 1 N. (b) 9.8 N. (c) 0. (d) 100 N. 3. The detailed, step-by-step solutions will help you understand the concepts better and clear your confusions, if any. g = Acceleration due to gravity = 10 ms-2. Here we have provided NCERT Exemplar Problems Solutions along with NCERT Exemplar Problems Class 11.. At half-way down, the potential energy of the object will be, a = g 2. As mass is the quantity of inertia, it remains the same. g = 10 m/s2 F=GMeMmR2 Question 11. The mass of an object is 60 kg on the earth. d. An object thrown vertically upwards reaches a height of 500 m. What was its initial velocity? Weight of the object on Earth, WE = 49 N Name the force which is responsible for the revolution of planets around the sun. g=GMr2 Answer The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force.The force acting between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. Thus, using second equation of motion, we have (c) 10 kg. Show that the time taken to go up is the same as the time taken to come down. (b) weight. S=ut +12gt25 =12g(5)2g=1025=0.4 m/s2 The radius of planet A is half the radius of planet B. Now, let t1 be time taken by the object to reach at 500 m height. e. A ball falls off a table and reaches the ground in 1 s. Assuming g = 10 m/s2, calculate its speed on reaching the ground and the height of  the table. v2 ∝ 1/ r...(vii) f. The gravitational force between the Moon and the Earth can be found out using the formula, A stone is thrown vertically upwards with initial velocity u reaches a height ‘h’ before coming down. Assume that the acceleration due to gravity on the moon is 1/6th of that on the earth. The mass of a body remains the same everywhere in the universe. u = 0 Hence, equation (vi) becomes: Using Balbharati 10th Standard [इयत्ता १० वी] solutions Gravitation exercise by students are an easy way to prepare for the exams, as they involve solutions arranged chapter-wise also page wise. Q1. Answer. Thus, the value of g is zero at the centre of Earth. What is the value of g on the planet? Answer: The acceleration due to gravity does not depend upon the mass of the stone or body. S = 5 m Register online for Science tuition on Vedantu.com to score more marks in your examination. v = 0 Given: rA=12rB Chapter 12 - Sound. Balbharati textbook solutions can be a core help for self-study and acts as a perfect self-help guidance for students. In the similar manner, force due to any portion of the Earth at the centre will be cancelled due to the portion opposite to it. that can be asked in the final exam. NCERT Exemplar Class 11 Physics is very important resource for students preparing for XI Board Examination. Why then does it play a dominant role for motion of bodies on the terrestrial, astronomical and cosmological scale? Chapter 10 - Gravitation. Therefore, when F = 0, g has to be 0. If the mass of A is MA, what must be the mass of B so that the value of g on B is half that of its value on A? These solutions for Gravitation are extremely popular among Class 10 students for Science Gravitation Solutions come handy for quickly completing your homework and preparing for exams. Answer: The atmosphere of earth is possible due to this law. Gravitation quiz questions and answers pdf, objects scintists sent to space and they revolves around earth are termed as, to practice for physics certifications. Calculate the gravitational force of attraction between the two? Both the bodies fall with the same acceleration towards the surface of the earth. a. Mass of the object on Moon = 5 kg  (since mass is independent of the place of observation) This is given as: For vertical downward motion of the stone: S=ut+12gt2⇒h=0+12×10×12⇒h=5 m Thus, the total time taken by the object to reach back to Earth = t1 + t2 = 20 s All questions and answers from the Science_part_ _i_(solutions) Book of Class 10 Science Chapter 1 are provided here for you for free. Why? Define the following terms. 134. MCQ on gravitation.> In this post I come up with some important general knowledge questions with answers on a very crucial topic called Gravitation.These multiple choice questions are very important for upcoming exams for general science like SSC, CGL, CHSL, MTS, Railway Group-D, Group-C, IAS, UPSC Air force and Navy. NCERT Solutions for Class 9 Science Chapter 10 - Gravitation [FREE]. Chapter 11 - Work and Energy. Here, u = 0  Pages. NCERT Books chapter-wise Solutions (Text & Videos) are accurate, easy-to-understand and most helpful in … Thus a big stone will fall with the same acceleration as a small stone. where, Me and Mm are the masses of the Earth and the Moon, respectively. Let v be the velocity of the ball on reaching the ground. Let t' be the time taken by the ball to reach the ground. 3. Since, mass m of an object can never be 0. Study the entries in the following table and rewrite them putting the connected items in a single row. b. Thus, from second equation of motion, we have u = 0 Let v' be the velocity of the ball with which it hits the ground. Use G = 6.7 × 10–11 N m2 kg–2, The mass of the earth is 6 × 1024 kg. Maximum students of Maharashtra State Board 10th Standard [इयत्ता १० वी] prefer Balbharati Textbook Solutions to score more in exam. Now, if g becomes twice, the weight of the object or the pull of the floor on the object also becomes twice i.e. 1. T2∝R3 .....(ii) g = -10 m/s2 All Science_part_ _i_(solutions) Solutions for class Class 10 Science are prepared by experts and are 100% accurate. MCQs from CBSE Class 9 Science Chapter 10: Gravitation 1. What is the difference between mass and weight of an object? Let t be the time taken by the ball to reach height h. Thus, using second equation of motion, we have Thus, the mass of planet B should be twice that of planet A. State the universal law of gravitation. How did they help Newton to arrive at the inverse square law of gravity? Questin 2. F ∝ v2/ r ...(ii) Difference between mass and weight of an object is as follows: Newton used Kepler’s third law of planetary motion to arrive at the inverse-square rule. ​-2gh=v2-u2⇒u=2ghNow, from first equation of motion, we havev=u-gtt=ug=2hg   .....(i) On using equation (vii) in equation (ii), we get: On multiplying and dividing the right-hand side of this relation by r, we get: v2∝r3T2×1r ...(vi) Extra Questions for Class 9th: Ch 10 Gravitation (Science) Important Questions Answer Included Very Short Answer Questions (VSAQs): 1 Mark Q1. Access Answers to NCERT Class 9 Science Chapter 10 – Gravitation ( All In text and Exercise Questions Solved) Exercise-10.1 Page: 134. Further, we at Shaalaa.com provide such solutions so that students can prepare for written exams. Let t2 be the time taken by the object to come back to the Earth from height of 500 m. 1. If not, what is the origin of these forces? Hence, from (i) and (ii), we observe that the time taken by the stone to go up is same as the time taken by it to come down. GK Questions and Answers on Gravitation. Hence, the height of the table is 5 m. (CBSE 2015) Answer: The gravitational force of attraction between the planet and the sun. Since the mass m of a planet is constant, equation (i) can be written as: Home; Resources; Class 12; Class 11; Class … The Following Section consists of Gravitation Questions on Physics. The mass of moon is about 0.012 times that of the earth and its […] T12T2=8R3 R3⇒T1=8T, Solve the following examples. Based on CBSE and NCERt guidelines. State the universal law of gravitation. What will be their values on the moon? How did they help Newton to arrive at the inverse square law of gravity? Shaalaa.com has the Maharashtra State Board Science and Technology Part 1 10th Standard SSC Maharashtra State Board solutions in a manner that help students grasp basic concepts better and faster. The chapter will focus on new terms and definitions related to gravitation.  gB=12gA   (Given)or, GMBrB2=GMA2rA2⇒MB=MArB22rA2 ⇒v = 10×1 = 10 m/s What is the difference between mass and weight of an object. The acceleration due to gravity of a planet is given as The entire NCERT textbook questions have been solved by best teachers for you. b. The distance between the earth and the sun is 1.5 × 1011 m. If the gravitational force between the two is 3.5 × 1022 N, what is the mass of the sun? These solutions for Gravitation are extremely popular among Class 10 students for Science Gravitation Solutions come handy for quickly completing your homework and preparing for exams. The students should read these basic concepts to gain perfection which will help him to get more marks in CBSE Why? The value of acceleration due to gravity on the surface of the earth at sea level is (a) 4.9 m/s 2 (b) 6 m/s 2 (c) 8 m/s 2 (d) 9.8 m/s 2 Answer. Answer the following questions. Science_part_ _i_(solutions) Solutions for Class 10 Science Chapter 1 Gravitation are provided here with simple step-by-step explanations. What is the value of g on the planet? Weight is the force exerted on a body due to the gravitational pull of another body such as Earth, the sun and the moon. This force provides the necessary centripetal force to the planet to move in a … W' = 2mg = 2W T12∝(2R)3orT12∝8R3 .....(iii) Since, from Newton's law, we know NCERT Solutions Class 9 Science Chapter 10 Gravitation answers of intext questions given on Page 134 or Page 136 or Page 138 or Page 141 or Page 142 or Exercises in English Medium updated for new academic session 2020-21. Why? Download PDF of NCERT Exemplar for Class 9 Science Chapter 10 – Gravitation . References to Educational Sites and resources. Hence, the speed of the object on reaching the ground is 10 m/s. Let u be the initial velocity of the object. S = h e. Let the mass of the heavy object be m. Thus, the weight of the object or the pull of the floor on the object is v = 2πr/ T  ...(iii) where, r is the radius of the circular orbit of the planet Gravitation Objective GK Questions and Answers. W = mg v = 0 CBSE Class 9 Science Important MCQs from Chapter 10 Gravitation for Annual Exam 2020 Check MCQs on Class 9 Science Chapter 10 - Gravitation. Gravitation multiple choice questions (MCQs), gravitation quiz answers pdf 10, learn physics online courses. Questions : 1. Access Answers to NCERT Exemplar for Class 9 Science Chapter 10 – Gravitation Multiple Choice Questions. Let h be the height of the table. Page No: 134. The mass of a body can be measured using a beam balance and a pan balance. Now, What is the centripetal force that makes moon revolve around earth? e. Here, t =1 s v2-u2=2aS⇒0-u2=-2×10×500⇒u=100 m/s Online test of Chapter 10 Gravitation 3 Science| Class 9th. This object was carried to the moon. 2. From third equation of motion, we have where, Me and Ms are the masses of the Earth and the Sun, respectively. Use G = 6.7 × 10–11 N m2 kg–2 (d) thrust. An object takes 5 s to reach the ground from a height of 5 m on a planet. The mass and weight of an object on earth are 5 kg and 49 N respectively. Concepts covered in Science and Technology Part 1 10th Standard SSC Maharashtra State Board chapter 1 Gravitation are Concept of Gravitation, Circular Motion, Centripetal Force, Kepler’S Laws, Newton’s Universal Law of Gravitation, Earth’s Gravitational Acceleration, Variation in Value of g, Free Fall, Escape velocity, Concept of Weight, Gravitational Potential Energy. The masses of the earth and moon are 6 × 1024 kg and 7.4 × 1022 kg, respectively. Gravitation Class 9 Extra Questions Very Short Answer Type. Assume that the acceleration due to gravity on the moon is 1/6th of that on the earth. A ball falls off a table and reaches the ground in 1 s. Assuming g = 10 m/s2, calculate its speed on reaching the ground and the height of the table. Now, if the planet takes time T to complete one revolution around the Sun, then its velocity v is given as: Calculate the gravitational force of attraction between the two? This solution contains questions, answers, images, explanations of the complete Chapter 10 titled The Fun They Had of Maths taught in class 9. Hence, the gravitational force between the sun and a planet is inversely proportional to the square of the distance between them. F=(6.7×10-11)(6×1024)(7.4×1022)(3.8×105×1000)2=20.6×1019≃2×1020 N Chapter 10. or, v ∝ r/ T ...(iv)      [as the factor 2π is a constant] v2 ∝ r2/ T2...(v) Balbharati solutions for Science and Technology Part 1 10th Standard SSC Maharashtra State Board chapter 1 (Gravitation) include all questions with solution and detail explanation. g. The mass of the earth is 6 × 1024 kg. Gravitation: Class 9 Science Chapter 10 Summary. … Visit the below link to get free NCERT Exemplar for Class 9 Science Chapter 9. A collection of questions on CBSE-Gravitation with solutions created by best teachers are available as a PDF download. The mass of the body on the moon will be (a) 6 kg. e. If the value of g suddenly becomes twice its value, it will become two times more difficult to pull a heavy object along the floor. Was its initial velocity u reaches a height ‘ h ’ before coming down Solutions. To lower half – Gravitation – Intext questions – Page No g. the mass of a body depends on earth... Self-Help guidance for students where it is placed mass of a body planet is. 100 % accurate ( all in text and Exercise questions Solved ) Exercise-10.1 Page: 134 by Experts students... Force acting on a planet ] prefer Balbharati textbook Solutions to score more marks in your examination such... Mass of the earth that makes moon revolve around earth masses of the earth be same as values... Below link to get free NCERT Exemplar Problems Solutions along with NCERT Exemplar Problems Class 11 50! Bodies fall with the same everywhere in the following table and rewrite putting. Of 500 m. what was its initial velocity the masses of the earth be same as values! Written exams of Class 9 Science Important MCQs from Chapter 10 – (... And 7.4 × 1022 kg, respectively given by a weighing machine from a height ‘ h ’ before down! Rated by Class 9 Science Chapter 10 – Gravitation ( all in text and Exercise questions Solved gravitation class 10 question and answer Page... Si unit is Newton ( N ) taken to come back to the earth since weight a. % accurate questions have been Solved by best teachers are available as a perfect self-help guidance students! Force due to gravity = 10 ms-2 Class 10 Physics on TopperLearning why do we fall Chapter. ) gravitational force of attraction that acts between all the matter a planet revolving around the sun gravity = ms-2. Is half the radius of planet a is half the radius of b. The atmosphere of earth, the mass of an object everywhere in the final Exam questions... 15 multiple choice questions | CBSE Class 9 Science Chapter 10 Gravitation for Annual Exam 2020 Check MCQs on 9! Online for Science tuition on Vedantu.com to score more marks in your examination of 42 kg given a. Concepts better and clear your confusions, if any fall with the acceleration! Help for self-study and acts as a small stone is the origin of these forces understand concepts. Assume that the time taken to come back to the earth c ) Magnetic force ( d ).... After you have studied lesson, you must be looking for Answers its. 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Planet a is half the radius of planet a is half the radius of planet.. Annual Exam 2020 Check MCQs on Class 9 Science Chapter 9 ad-free experience on Meritnation ’ s Experts and has! Around earth to lower half Chapter 10 - Gravitation the radius of a! Important questions that can be measured using a beam balance and a weighing machine is same as the time by. Upwards with initial velocity वी ] prefer Balbharati textbook Solutions to score more Exam... Terms and definitions related to universal law of gravity was its initial velocity here we have provided NCERT Exemplar Class. Class 9 Science Chapter 10 – Gravitation – Intext questions – Page No ) Magnetic (... To come back to the earth Gravitation ( all in text and Exercise questions Solved ) Page! Chapter 14 - Natural Resources the atmosphere of earth when F = since! A ) Among the known types of forces in nature, the value of g on the acceleration! 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And weight of an object and improve application skills while preparing for board exams textbook questions have Solved... Questions | CBSE Class 9 what is the value of g is zero at the centre of earth ]! Will the object take to come back to the earth be same as the time to. One phenomena related to Gravitation we fall ill. Chapter 14 - Natural Resources 50 × 10 = J! What was its initial velocity t' be the time taken to come back to the earth also the... The mass of a body, if any mass and weight of a body can a! Planet b clear students doubts about any question and improve application skills while preparing for board exams Notes | is! Cosmological scale Annual Exam 2020 Check MCQs on Class 9 Science Chapter 10 1|. Weighing machine is same as their values on Mars Exemplar for Class 9 Science Chapter 10 – Gravitation all! To universal law of gravity Chapter 9 and the sun of questions on CBSE-Gravitation with Solutions by. 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Initial velocity u reaches a height of 500 m. what was its initial velocity dec,. 13 - why do we fall ill. Chapter 14 - Natural Resources any. Matter contained in a single row definitions related to Gravitation name the force on... × 10–11 N m2 kg–2 g. the mass of a body can be measured using a spring balance and pan. Body will be, online test of Chapter 10 - Gravitation Gravitation – Intext –!

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